CUIT calculates preliminary PUE


Written on December 16, 2009 – 3:06 pm | by rh311

PUE = Total Facility Load / IT Load

  • IT Load = 250kW (pp1,2,3,4,5,6,16) + 40kW (pp26,27) = 290kW
  • Total Facility Load (winter w/o chw) = 290kW (IT) + 50kW (ATS2) + 85kW (ATS3 lieberts w/o chw) = 425kW
  • Total Facility Load (w/chw) = 290kW (IT) + ??kW (ATS2) + 50kW (ATS3 lieberts w/chw) + ??kW (load of chiller plant) = ??kW

PUE (w/o chw) = 425 / 290 = 1.465 (too good to be true!)

NOTE: Need power from chiller plant to get PUE (w/chw), but the numbers we have make it seem like our efficiency is not that bad. 290kW is the power after the UPS’s. We need to do some further research to figure out how much power is lost to the plug of the servers themselves.

If we do a rpugh calculation assuming the Avg Power Factor on most of our rack mounted UPS’s is 0.8 then (290 * 0.8 = 232)

PUE (winter w/o chw) = 425 / 232 = 1.832 (probably closer to reality, but this is the winter)